If you really need to escape with a single backslash instead of the double backslash, you can do the following method. It is trivial to implement, but it seems to me that this functionality belongs to the language - the implementation obviously knows better which characters must. The most straightforward way to escape a special regex character is with the re.escape() function escapes all special regex characters with a double backslash, such as the asterisk, dot, square bracket operators. How to accomplish this in Python? Method: re.escape() Precede a metacharacter with a backslash () 2. In other words, to force them to be treated as ordinary characters. JavaScript Regular Expression To Replace Escape Special Characters From Java Regex Replace All Characters With Except Instances Of A Given Problems With. with a single backslash \.įor example, the string 'hello-$100' should be transformed to: 'hello\-\\-\$100' According to the Java API documentation for regular expressions, there are two ways in which we can escape characters that have special meaning. Say, you want to escape the characters -]\^$*. or regex asterisk * operators by escaping them with \. For example, to match the dot or asterisk characters '.' and '*', you must first get rid of the special meanings of the regex dot. In regular expressions, you can use the single escape to remove the special meaning of regex symbols. Is there any method in Java or any open source library for escaping (not quoting) a special character (meta-character), in order to use it as a regular expression This would be very handy in dynamically building a regular expression, without having to manually escape each individual character. You can find complete list of String escapes over this java doc. For example, the tabular whitespace '\t' and newline '\n'. Double quotes characters can be escaped with backslash( ) in java. The backslash escape character '\' is a special Python string character that is usually followed by an alphabetic character.
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